The Waiter
Three men in a cafe order a meal the total cost of which is $15. They each contribute $5. The waiter takes the money to the chef who recognizes the three as friends and asks the waiter to return $5 to the men.
The waiter is not only poor at mathematics but dishonest and instead of going to the trouble of splitting the $5 between the three he simply gives them $1 each and pockets the remaining $2 for himself.
Now, each of the men effectively paid $4, the total paid is therefore $12. Add the $2 in the waiters pocket and this comes to $14…..where has the other $1 gone from the original $15?


mbl said,
July 15, 2008 @ 2:37 am
Let see the situation,
the equality is
$5 + $5 + $5 = $10 + $1 + $1 + $1 + $2………….Eq.1
now each men $1 back, and the equality takes form like bellow,
($5 - $1) + ($5 - $1) + ($5 - $1) = $10 + $2………..Eq.2a
$4 + $4 + $4 = $10 + $2………..Eq.2b
this equality is not wrong. The effective payment is $12 (left handside of Eq.2b) and we see the $12 on the right handside of Eq.2b. It’s no meaning trying to find $15 while it is $12.
It seems politicians are using such “mental” techniques to fake us (voters)…
:-)